Series Anser
Please help with my answers to this question - what should I do?
1 a pure resistance of 300 ohms and an inductance pure is connected in series to 2.5H with a 200V, 50Hz supply. calculate a single - the inductive reactance XL b - the impedance Z c - the way I spend d - voltage across each component and VI and VR - factor f circuit power - the relationship between the circuit voltage and tried to pass the Anser But if they are correct u can help me please because I did - 2 x Pie x 50 x 2.5 = 785 ohms B - 300 / 2 + 785 / 2 = response square root, and for c 840.37 - 200/300 = 0.6666 is the rite d - VR = 0.666 x 300 = 199.8 vl = 0.666 x 785 = 522.81 E - Power factor cos 140 = -0 , 76 f-voltage LAG are my outs Woking fine or poorly
a) Correct. B) law. C) incorrect. V = I * Z. Therefore, I = V / Z. He used 300-ohm impedance and have not found it in (b). I = 200/840.37 = .238 A. d) False. Method is appropriate, but the fact of being ill (c), responses were incorrect. VR = 300 *. 238 = 71.4V. VI = 785 *. 238 = 186.83 V. e) incorrect (again, the current was wrong). Pr = 71.4 *. 238 = 17W. PL = 186.63 *. 238 = 44.5 VAR. Angle = arctan (44.5 / 170 = 69.1 degrees. PF = cos (69.1) = 0.36. F) Quick note on this point. The advancement or retardation is always described as the current tension. Thus, in this case, the power factor is lagging (inductors always lag).
